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scx_lavd: further prioritize producers over consumers

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That is because many latency-critical tasks are producers.

Signed-off-by: Changwoo Min <changwoo@igalia.com>
This commit is contained in:
Changwoo Min 2024-07-28 15:38:54 +09:00
parent 7106e8cdca
commit 221f1fe12a
1 changed files with 10 additions and 6 deletions
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16
scheds/rust/scx_lavd/src/bpf/main.bpf.c
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@ -1069,9 +1069,9 @@ static void calc_lat_cri(struct task_struct *p, struct task_ctx *taskc)
/*
* Wake frequency and wait frequency represent how much a task is used
* for a producer and a consumer, respectively. If both are high, the
* task is in the middle of a task chain.
* task is in the middle of a task chain. We prioritize a producer.
*/
lat_cri_raw = wait_freq_ft * wake_freq_ft;
lat_cri_raw = wait_freq_ft * wake_freq_ft * wake_freq_ft;
/*
* The ratio above tends to follow an exponentially skewed
@ -1244,7 +1244,7 @@ static void update_stat_for_running(struct task_struct *p,
u64 wait_period, interval;
u64 now = bpf_ktime_get_ns();
u64 load_actual_ft, wait_freq_ft, wake_freq_ft;
u64 perf_cri_raw;
u64 perf_cri, perf_cri_raw;
/*
* Update the current logical clock.
@ -1299,9 +1299,13 @@ static void update_stat_for_running(struct task_struct *p,
load_actual_ft = calc_runtime_factor(taskc->load_actual);
wait_freq_ft = calc_freq_factor(taskc->wait_freq);
wake_freq_ft = calc_freq_factor(taskc->wake_freq);
perf_cri_raw = load_actual_ft * p->scx.weight *
wait_freq_ft * wake_freq_ft;
taskc->perf_cri = log2_u64(perf_cri_raw + 1);
perf_cri_raw = load_actual_ft * p->scx.weight;
perf_cri = log2_u64(perf_cri_raw + 1);
perf_cri_raw = wait_freq_ft * wake_freq_ft * wake_freq_ft;
perf_cri += log2_u64(perf_cri_raw + 1);
taskc->perf_cri = perf_cri;
cpuc->sum_perf_cri += taskc->perf_cri;
/*